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Compose in apply to each - returns array

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Posted on by Popky

Can someone please explain me or provide any documentation why "compose" in "apply to each" behave like an array and not just a string? I would expect that "compose" result in this example will return "3" but for some reason returns an array of "[1, 2, 3]".

Why? How from string action can became array?

I've seen it in numerous blog posts as a time saver instead of using "append to variable", but never understood why "compose" behave like this.

Example:

Input: [1,2,3] Output: [1,2,3]

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fchopo 8,003 Moderator on at

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Hi @Popky

I see you're referencing output of "compose 2" outside of the apply to each action, which wouldn't have much sense (compose 3 action). Basically, "compose 3" should be within the apply for each loop.

"Compose 2" should return each item of the array, and not the full array.

Hope that helps!

Ferran

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Popky 31 on at

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This post is purely for educational manners, not looking for fix or workaround tbh.
It does not make much sense I am looking for someone to explain me why its behaving like this with this setup. "Compose 3" here is just for log purpose to display content of "Compose 2" from "apply to each" > [1, 2, 3].

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adedapo 256 on at

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This is the behaviour of some data operation actions like Compose, Select and Filter.

When accessed outside of a non-nested apply to each, their output becomes an array of the values in the loop. This is the current behaviour but it is not well documented.

This can be useful if you want to replace append to array variable because the loop's concurrent settings can now be set to the maximum thereby improving the flow's performance.

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