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Power Platform Community / Forums / Power Automate / Take Person field (mul...
Power Automate
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Take Person field (multiple lines) from SP list and place display name in html table in email

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Posted on by 104

I have a get items action that then feeds into below, it all works as expected except for the 'EscalatedTo' field.  This is a person field (potentially could have more than one person per field) in a sharepoint list.  If I place the dynamic reference to 'EscalatedTo' in the Select table, it returns all the claims details.  I only want to show display name. 

 

tatmaninov_0-1668845201325.png

 

I also try this below, with expression items('Apply_to_each')?['EscalatedTo'][0]?['DisplayName'] which does give me the display name I want, but it just repeats the first row of the table, feel like I am close to the solution, can anyone help me over the line?

tatmaninov_1-1668845366179.png

 

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  • grantjenkins Profile Picture
    11,063 Moderator on at

    At the moment, if you had 20 items in your List then you would create an HTML table with 20 items, 20 times.

     

    Your Select shouldn't be inside an Apply to each. Below is what you're after in terms of creating the HTML table.

     

    grantjenkins_0-1668869250242.png

     

    I'll provide a solution for the multiple Persons tomorrow for you as just off to sleep now (almost 1AM where I am).

     

    It's a bit tricky to get the multi-select values when you're not using a loop but can definitely achieve what you're after just within the Select.

  • tatmaninov Profile Picture
    104 on at

    Thanks for the reply @grantjenkins , 20 tables was not my intention, just one table with a 1 row for each row of the returned get items.  When I try to modify the field in Select table I get the error that it cannot have any parameters.  If you can offer a solution that would be much appreciated.

  • tatmaninov Profile Picture
    104 on at

    After some additional experimenting I get this to work as desired, only annoyance is that if there is more than one person in a particular row, I am not sure how to add a conditional delimiter i.e. only use delimiter if person count is greater than 1.

     

    @grantjenkins sounded like your solution may be alot simpler than what I have done, which would be good.

     

    tatmaninov_0-1668891474634.png

     

  • Verified answer
    grantjenkins Profile Picture
    11,063 Moderator on at

    To get the list of Display Names I would use XML and XPath. This will allow us to not require a loop making it much more efficient and cleaner.

     

    In my example I've got a list with two multi-select columns. One of type Person (Members) and one of type Choice (Countries).

    grantjenkins_0-1668901732879.png

     

    Below is the full flow. I'll go into each of the actions.

    grantjenkins_1-1668901922664.png

     

    Get items returns all the items from my list.

    grantjenkins_2-1668901986134.png

     

    XML is a Compose action that converts our JSON output from Get items into a valid XML document. We use concat to wrap the output into a root element to ensure it's valid XML. The expression we use here is:

    xml(json(concat('{"root": ', outputs('Get_items')?['body'], '}')))

    grantjenkins_3-1668902108901.png

     

    Next, we can build up our table of data using a Select. It takes in value from Get items.

    grantjenkins_4-1668902254039.png

     

    The two expressions to get the list of Members and Countries are below. They build up an XPath expression using the ID from the current item, then wrapped in a join expression to join each member/country with ", ".

     

    For the Members we want to get the DisplayName since it's a Person field. And Countries is a Choice field, so we want Value. You would just need to change the Person field to use the name of your field.

    join(xpath(outputs('XML'), concat('//value[ID=', item()?['ID'], ']/Members/DisplayName/text()')), ', ')
    
    join(xpath(outputs('XML'), concat('//value[ID=', item()?['ID'], ']/Countries/Value/text()')), ', ')

     

    This will give us the following JSON.

    [
     {
     "Title": "Team 01",
     "Members": "Adele Vance, Lee Gu, Megan Bowen",
     "Countries": "USA, Canada"
     },
     {
     "Title": "Team 02",
     "Members": "Diego Siciliani, Patti Fernandez",
     "Countries": "China, Australia, England"
     },
     {
     "Title": "Team 03",
     "Members": "Adele Vance, Patti Fernandez",
     "Countries": "USA"
     },
     {
     "Title": "Test 04",
     "Members": "Joni Sherman, Johanna Lorenz",
     "Countries": "USA, Canada, China, England"
     },
     {
     "Title": "Test 05",
     "Members": "Johanna Lorenz, Joni Sherman",
     "Countries": "China, Australia"
     },
     {
     "Title": "Test 06",
     "Members": "Johanna Lorenz, Diego Siciliani",
     "Countries": "Canada, England"
     },
     {
     "Title": "Test 07",
     "Members": "Joni Sherman, Nestor Wilke",
     "Countries": "England, USA"
     },
     {
     "Title": "Test 08",
     "Members": "Johanna Lorenz, Lee Gu, Lynne Robbins",
     "Countries": "USA, Canada, China"
     },
     {
     "Title": "Test 09",
     "Members": "Lynne Robbins, Nestor Wilke",
     "Countries": "USA, Canada, Australia, England"
     }
    ]

     

    We can then use the output from our Select for Create HTML table as so.

    grantjenkins_5-1668902492906.png

     

    And the output of our HTML table is:

    grantjenkins_6-1668902508450.png

     

     

     

  • tatmaninov Profile Picture
    104 on at

    Wow, thank you so much.  I much prefer this method, as you say it is a lot more efficient.

     

    Appreciate you taking the time to share this and go through the details explaining it.

  • indras111 Profile Picture
    22 on at

    @grantjenkins , I am getting blank in person field. Can you please let me know what i maybe doing wrong here? I have followed same exact process you have outlined here.

     

    indras111_0-1694415430646.png

     

    indras111_1-1694415465423.png

     

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