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How to convert Forms Likert Scale into value and compute average?

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Posted on by dsFra

I am using a 6 point Likert Scale in Forms ("Oustanding", "Beyond Expectation", "Meets Expectation", "Below Expectation", "Issue", "Unknown"). I have 9 items, which are assessed along these lines.

How can I transform the data in Flow efficiently into values from 5 ("Oustanding") to 1 ("Issue") and compute the average of these values (with "Unknown" being ignored in the computation of the mean)?

Thanks!

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v-zhos-msft on at

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Hi @dsFra ,

I am afraid that there is no way to achieve your needs in Microsoft Flow currently.

According to your discription, first, we need get the 6 point, then transform the points into values.

However, in MS flow, we can only get the response details but not the form details.

Here is a similar idea you can vote with:

https://powerusers.microsoft.com/t5/Flow-Ideas/Microsoft-Form-Return-form-details/idi-p/71336?advanced=false&collapse_discussion=true&filter=location&location=idea-board:FlowIdeas&q=get%20the%20forms%20details&search_type=thread

Best Regards,

Community Support Team _ Zhongys

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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dsFra 7 on at

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Thanks for your reply. But is there really no way?

I would just need to create some hard coded variable transformation: if the answer equals "Oustanding" then assign value "5", if "Beyond Expecation" assign "4" etc. In the end I need to compute an average and that's it.

I was trying to do this with an expression in the logic of "if(equals(...,"Outstanding),5,if(equals(...,"Beyond Expectation"),4, ... etc ... )). It didn't give me the right result, unfortunately, but maybe I had just a simple flaw in there.

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AlanPs1 2,471 on at

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Hi @dsFra

This is possible but not straight forward.

I see where you are going with "if(equals(...,"Outstanding),5,if(equals(...,"Beyond Expectation"),4, ... etc ... ))" and what I propose below, may be able to further enhanced but here is a working example that has been tested and does provide the results you are looking for in a float so 1.5 is possible when averaging off the final compute.

Here is the form:

Here is the Flow

Here are the actions and expressions:

if(equals(variables('Q1'), 'Oustanding'),int('5'),if(equals(variables('Q1'), 'Beyond Expectation'),int('4'),if(equals(variables('Q1'), 'Meets Expectation'),int('3'),if(equals(variables('Q1'), 'Below Expectation'),int('2'),if(equals(variables('Q1'), 'Issue'),int('1'),if(equals(variables('Q1'), 'Unknown'),int('0'),''))))))

if(equals(variables('Q2'), 'Oustanding'),int('5'),if(equals(variables('Q2'), 'Beyond Expectation'),int('4'),if(equals(variables('Q2'), 'Meets Expectation'),int('3'),if(equals(variables('Q2'), 'Below Expectation'),int('2'),if(equals(variables('Q2'), 'Issue'),int('1'),if(equals(variables('Q2'), 'Unknown'),int('0'),''))))))

if(equals(variables('Q3'), 'Oustanding'),int('5'),if(equals(variables('Q3'), 'Beyond Expectation'),int('4'),if(equals(variables('Q3'), 'Meets Expectation'),int('3'),if(equals(variables('Q3'), 'Below Expectation'),int('2'),if(equals(variables('Q3'), 'Issue'),int('1'),if(equals(variables('Q3'), 'Unknown'),int('0'),''))))))

div(add(add(variables('A1'), variables('A2')), variables('A3')), variables('Divider'))

If implemented as above for 3 questions it works. You would need to scale out to suit you.

If you have found my post helpful, please mark thumbs up.

If this post has solved your problem, please click "Accept as Solution".

Any other questions, just ask.

Thanks, Alan

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dsFra 7 on at

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Works perfectly. Thanks a lot!

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AlanPs1 2,471 on at

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You’re most welcome.
Happy Flowing.
Thanks, Alan

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Ranners66 3 on at

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Thanks Alan this really helped me.

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