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Power Platform Community / Forums / Power Automate - Using Flows / Changing a date format
Power Automate - Using Flows
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Changing a date format

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Posted on by bebo987 98

Hi Community!

 

I have this little issue to fix: 

I'm building a flow that fetches information from an automated email message. In this one we get a date and time in the format that follows:

bebo987_0-1683046138815.png

however we need to plit this into DD/MM/YYY and separately HH:MM:SS. 

how can i get to that result?

 

thank you for your help

  • Nived_Nambiar Profile Picture
    Nived_Nambiar 17,497 Super User 2025 Season 1 on at
    Re: Changing a date format

    Hi @bebo987 

     

    In sharepoint, I think date is stored in format of MM/dd/yyyy, that is why you got date stored as MM/dd/yyyy under datetime column.

     

    May be use a text column and store the date there, it would preserve the dateformat as dd/MM/yyyy 🙂

     

  • bebo987 Profile Picture
    bebo987 98 on at
    Re: Changing a date format

    HI @Anonymous 

     

    IT WORKS FINE ALTHOUGH THE VALUE EXTRACTED IS INSERTED INTO A SHAREPOINT LIST BUT INSTEAD OF COMING OUT AS DD/MM/YYYY COMES AS MM/DD/YYYY WHICH IS WRONG.

     

    THE FORMULA IN POWER PLATFORM IS: 

    formatDAteTime(trim(split(outputs('Cleanup_date_and_time_to_text'),'@')?[0]),'dd/MM/yyy')
     
    AND I HAVE TRIED TO CHANGE FORMAT IN SHAREPOINT HOWEVER NO SUCCESS. DO YOU HAVE ANY IDEA WHY
  • Verified answer
    Nived_Nambiar Profile Picture
    Nived_Nambiar 17,497 Super User 2025 Season 1 on at
    Re: Changing a date format

    Hi @bebo987 

     

    Try this approach 

     

    Nived_Nambiar_0-1683048728448.png

     

    expression : 

    replace(replace(replace(replace(outputs('date_and_time_to_text')?['body'],'["',''),'"]',''),'.',' '),decodeUriComponent('%27'),'')
     
    this is to cleanup unecessary characters from the text.
     
    Nived_Nambiar_1-1683048788029.png

     

    expression: 

    formatDateTime(trim(split(outputs('Compose'),'@')?[0]),'dd/MM/yyy')
     
    this is to obtain date in dd/MM/yyy format
     
    Nived_Nambiar_2-1683048825515.png

     

    expression: 

    formatDateTime(trim(split(outputs('Compose'),'@')?[1]),'HH:mm:ss')
     
     
    Result
    Nived_Nambiar_3-1683048864238.png

     

     

     

    Hope it helps

     

    Mark it as solution if it resolves your query !

     

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