Thank you, abm. My level of expertise on building expressions is extremely limited at this time, but I did get this to work:
1. List Files In Folder
2. Apply To Each
3. Add A Row Into A Table
In one of my output fields, I used the following: replace(items('Apply_to_each')['Path'],items('Apply_to_each')['Name'],'')
Your solution sounds interesting, but I don't yet understand how to write a series of steps for "apply to each". I do eventually need to learn how to use multiple steps with variables and compose, as you have done. I don't know if my expression above is as simple as it could be, but at least it works. If you have suggestions on how to improve it, I'm listening. I was wishing that Expressions would help me more than it did. I think it has done better in the past, so I must have done it differently this time.
You gave me the idea of using replace and some syntax for doing that. Instead of parsing the path, I just stripped off the file name.
