Label Visibility with an If statement in a form viewer?

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Posted on by kayakingaway

Hello,

I am attempting to add a label that would only show if a data card in my form viewer was set to "HS Approved".

I have tried ...

If(Gallery1_6.Selected),(DataCardValue16_1.Selected.Value = "HS Approved", true, false)

If((DataCardValue16_1.Selected.Value = "HS Approved"), true, false)

If((DataCardValue16_1.Text = "HS Approved"), true, false)

If(Value(DataCardValue16_1.Text) = " HS Approved", true, false)

& about a million variations of this but I cannot seem to get it to work. I have several labels set with a visibility if statement throughout my app but for some reason I am having trouble setting this one based on the info in the form viewer, any help would be appreciated!

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BideyYusuf 387 on at

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Hello @kayakingaway First of all.... If the Datacardcontrol value you want to base the visibility of the Label on is a Text.... then on the visible property of the Label put:
if(Datacardcontrol.Text = "HS Approved",true,false)
but if the DatacardControl is a dropdown or combobox control.....you put.
If(Datacardcontrol.selected.value = "HS Approved",true,false)

let me know if this works for you

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kayakingaway 52 on at

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Hi!

Thanks for the suggestions. When I click on the field I am using it is listed as a Combo Box titled "DataCardValue16_1". I tried both of your suggestions and both gave me the "Incompatible types for comparison. These types can't be compared. I am thinking something needs to be different since it is displaying the form based on a gallery selection.

On initial entry into a normal form I have a formula...
If((DataCardValue33.Selected.Value)= "HS Approved", true, false)

& it works perfectly to only show the label when the HS Approved is chosen. But when I try to use a similar formula in the gallery/form viewer I get an error.

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Drrickryp Super User 2024 Season 1 on at

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@kayakingaway

You never need an If() formula for a visible property since the equation reduces to true or false without it. For example: DataCardValue33.Selected.Value= "HS Approved" is either true or false.

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Drrickryp Super User 2024 Season 1 on at

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@kayakingaway

You never need an If() formula for a visible property since the equation reduces to true or false without it. For example: DataCardValue33.Selected.Value= "HS Approved" is either true or false. You are making it unnecessarily complicated and introducing a source of error.

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BideyYusuf 387 on at

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Hi @kayakingaway On the form Viewer we might have to do it separately.

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kayakingaway 52 on at

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Hello,

Please see image.

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BideyYusuf 387 on at

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@kayakingaway in this case, since FormViewer is display form, you will need to put the control on the Form Viewer separately. For example... if the DataCardValue16_1control is showing "HS Approved"
On the visible property of the Datacard of the LabelText ...
put the formula : DataCardValue16_1.Selected.Value = "HS Approved"

Hope this clarifies it for you.

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BideyYusuf 387 on at

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Hi @kayakingaway
in this case, since FormViewer is display form, you will need to put the control on the Form Viewer separately. For example... if the DataCardValue16_1control is showing "HS Approved"
On the visible property of the Datacard of the LabelText ...
put the formula : DataCardValue16_1.Selected.Value = "HS Approved"

Try this and let me know if it works for you.

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