Answered

Remove() does not work when combined with additional commands.

(1) Share

Report

Posted on by MT-08080833-0

Hey!

I want to include a button on my screen that removes a selected item from my gallery. Now the Remove function works fine if used alone as a command. But as soon as I add an additonal command (e.g. Navigate) it returns an Argument Type error for the Remove function.

Remove('SPdatasource'; varSelection) & Navigate('Success') & Set(varGalDefault; Blank()) & Set(varGalDefault; {})
Remove command                       & Navigation to Success screen                      & Set the gallery default value to {} so it goes back to no selected item after deleting an account.
 
OnSelect of gallery:
Set(varSelection; ThisItem)
 
Thank you for your help. Happy to provide more context if needed.
 
Mathias

Categories:

Using Apps Using Formulas

All responses (2)

Answers (1)

MT-08080833-0 6 on at

Like (1)

Report

Remove() does not work when combined with additional commands.

Thank you, works fine! I still need to figure out where/when to use which separators.
Verified answer

WarrenBelz 146,668 Most Valuable Professional on at

Like (2)

Report
Remove() does not work when combined with additional commands.

Try with these separators
Remove( 'SPdatasource'; varSelection );; Navigate('Success');; Set( varGalDefault; Blank() );; Set( varGalDefault; {} )

Please click Does this answer your question if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it a Like.
MVP (Business Applications) Visit my blog Practical Power Apps Buy me a coffee