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Power Automate
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GroupBy on createdby

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filter(Microsoft.Dynamics.CRM.Today(PropertyName='createdon'))/groupby((createdby/fullname),aggregate($count as activity_count))

 

I am getting an error "Systemuser doesn't contain an attribute name ownerid". I am not using ownerid. Any suggestions would be appreciated.

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  • v-zhos-msft Profile Picture
    on at

    Hi @Anonymous ,

    Could you please share a screenshot of your flow's configuration?

    It seems you want to filter the records of a dynamic entity.

    Could you please explain your scenario more clearly?

    Best Regards,

    Community Support Team _ Zhongys

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

  • Community Power Platform Member Profile Picture
    on at

     

    I am trying to get count of activites created today group by Createdby. For this, I am using List record template of Commom Data Service.

  • v-zhos-msft Profile Picture
    on at

    Hi @Anonymous ,

    It seems you want to get the records which was created on today and order by createdby.

    I have made a flow for your scenario, please check it for a reference.

    Capture5.PNG

    Best Regards,

    Community Support Team _ Zhongys

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

  • Community Power Platform Member Profile Picture
    on at

    Thanks for help. But I am looking for group by createdby user to get count of all activities created by user today.

  • v-zhos-msft Profile Picture
    on at

    Hi @Anonymous ,

    I am afraid that there is no way to achieve your needs in Microsoft Flow currently.

    There is no options about group by with the 'List records' action.

    You can use the 'Filter array' action to get the records you want.

    Capture3.PNG

    Best Regards,

    Community Support Team _ Zhongys

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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