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Format decimal numbers

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Posted on by Damo_R

I am trying to format the data of a calculated field within the flow to send in an email to show 2 decimal places. has anyone acheived this?

I have tried both Text and Round and several iterations of these functions and they come back as invalid templates.

Can anyone shine any light on this?

the value from the column is 1.50000000000 i only want to see 1.5

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efialttes 14,756 on at

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As far as I know, math functions currently supported in Microsoft FLow as "expressions" are the ones defined here:
https://docs.microsoft.com/en-us/azure/logic-apps/logic-apps-workflow-definition-language

I guess you can multiply by 100, convert into integer, get back to float and divide into 100; but I haven't tested myself; so unsure if both float() and int() accepts non-string parameters

Hope this helps

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Damo_R 34 on at

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@efialttes thank you so much for your repsponse and the link you provided. With a little reading and some trial and error i have come up with the following:

if(or(greater(body('Create_item')?['Days_x0020_Total'], string (10)),equals(body('Create_item')?['Days_x0020_Total'],string(10))),take(body('Create_item')?['Days_x0020_Total'],4),take(body('Create_item')?['Days_x0020_Total'],3))

This basically looks at the value in the total days field and determines if it is greater or equal to 10, if yes then it will produce 4 place and if no it will produce 3 places.

works a treat

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efialttes 14,756 on at

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@Damo_R
You are welcome. Thanks for sharing!

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StevenWade 129 on at

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There's still no generalized rounding solution in Flow, which means building solutions specific to your data. Here's an approach I took when I needed to round from three decimals (#.###) to two (#.##) for display purposes. Fortunately, I knew I'd always be getting data in a #.### format, but you could pretty easily extend this to find the decimal place if the number of places to the left of the decimal was unknown.

if(contains('56789', substring(string(triggerBody()['number']),4,1)),substring(string(add(triggerBody()['number'],0.01)),0,4),substring(string(triggerBody()['number']),0,4))

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Community Power Pla... on at

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I just used your suggestion to round the result of my division formula:
Original expression:
div(variables('Sum'),5)
Which returned the full result, i.e 1.6666666 or similar.

I formatted it to 1 decimal using this expression:
div(float(int(mul(div(variables('Sum'),5),10))),10)

that is
take result from division
multiple by 10
converting to int
converting to float (else it became an integer result)
dividing by 10

Thanks for the hint!

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jan-dolejsi 8 on at

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It was not as simple, because int() and float() only accept string arguments. So you get a run-time error like this:

InvalidTemplate. Unable to process template language expressions in action 'Rounded' inputs at line '1' and column '2484': 'The template language function 'int' was invoked with a parameter that is not valid. The value cannot be converted to the target type.'.

On top of that, the int() function only accepts string representations of integer numbers - it does not accept any floating point number. So I had to turn the number to string, select the part before the '.' and pass it to int(). Not sure if the '.' is subject to localization, which would obviously fail.

This is the expression I've put into a Compose action:
div(int(first(split(string(mul(123.456, 10.0)),'.'))), 10.0)
The output was
123.4

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aCTim 2 on at

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Thanks to Damo_R I was able to round numbers for our case, with two numbers behind. A little bit ugly, but it works.

Initializing 2 variables.
variable var as string
first(split(string(mul(123.454, 1000.0)),'.'))
(you can put your number or varible where 123.454 is)
variable varTemp as Integer
int(variables('var'))
than we go on with a condition
if
int(last(variables('var')))
equal or even to 5

set var to
sub(add(int(variables('varTemp')),10),int(last(string(variables('varTemp')))))
else
set var to
sub(int(variables('varTemp')),int(last(string(variables('varTemp')))))
finally transform it to a float (int would slice the numer)
div(float(int(div(int(variables('var')),10))),100)

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Damo_R 34 on at

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Glad my efforts could help you

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degvalentine 195 on at

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Here's a similar solution, but no temp variables are needed.
Uses variables('myFloat') to represent the number you want to round.
div(
add(
mul(variables('myFloat'), 1000),
sub(
if(
greaterOrEquals(
mod(mul(variables('myFloat'), 1000), 10),
5
),
10,
0
),
mod(mul(variables('myFloat'), 1000), 10)
)
),
1000
)
Or, all in one line:
div(add(mul(variables('myFloat'),1000),sub(if(greaterOrEquals(mod(mul(variables('myFloat'),1000),10),5),10,0),mod(mul(variables('myFloat'),1000),10))),1000)
The float is multilpiled by 1000 before doing modulo to avoid tiny-fraction math errors (e.g. returning 0.00499999... instead of 0.005).

Using add, sub, mul, div, and mod to round a float... a reasonable workaround... XD

If you're looking for an expression to format for currency with a thousands separator, see my expression in another post.

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nsauter23 8 on at

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This can be done with the following

substring(string(triggerOutputs()?['body/tileValue'])),0,3)
Don't forget the decimal '.' counts as a character because this is a string not an actual intager. It is not actual rounding, but it accomplished what I needed for my email to look cleaner.

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