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Power Platform Community / Forums / Power Automate / Flow does not find dat...
Power Automate
Suggested Answer

Flow does not find date in excel

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Posted on by 32
Hello
 
I am building a flow that takes figures from Power BI and writes it to a row in excel that is pre populated with todays date. I keep getting the following error message. In key value i have 
formatDateTime(utcNow(), 'dd/MM/yyyy')
 
I am just using hard coded variables at the moment before i try getting the figures automatically from power bi.
 
 
 
"message""No row was found with Id '14/08/2024'
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  • Suggested answer
    David_MA Profile Picture
    14,354 Super User 2026 Season 1 on at
    Try expanding the advanced options in the Excel action and choose ISO8601 date format. You will also need to format your expression to use the ISO8601 format as well, which is yyyy-MM-dd.
  • Wishamaster89 Profile Picture
    32 on at
    Thanks but that didn't fix it. In excel the date is formatted as date which i assume is correct?
  • Chriddle Profile Picture
    8,685 Super User 2026 Season 1 on at
    What Excel shows you only has a marginal connection to how the data is stored internally and transferred to the Power Automate Connector ;)
    I would think again about @David_MA 's tip
  • Wishamaster89 Profile Picture
    32 on at
    I have tried what David suggested but unfortunately the data flow is still failing.
     
     
     
    {
      "status"404,
      "message""No row was found with Id '2024-08-16'.
  • Wishamaster89 Profile Picture
    32 on at
    I've  figured it out, i had to convert the dates in excel to text using the iso format. That has now solved the issue.
     
    Thanks for your help.
  • Chriddle Profile Picture
    8,685 Super User 2026 Season 1 on at
    I don't recommend to change the Excel's data type.

    To identify the Excel row via "Key value" you have to use the number that represents the date in Excel.
    (Even if you have set DateTime Format to ISO 8601, which is always a good idea)
     
    To calculate the Key value, use the following expression:
    add(
    	div(
    		sub(
    			ticks('2024-08-17'),
    			ticks('1900-01-01T00:00:00Z')
    		),
    		864000000000
    	),
    	2
    )
    where '2024-08-17' is the date you are looking for.
     
     

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