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Remove value in each key of JSON object

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Posted on by PR001

Hi all - i am looking to remove any spaces that may be a value in a JSON object. Would anyone know the most efficient way to do this without having to declare each key in a Compose statement? Perhaps by looping through each key? Thanks!

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takolota1 4,974 Moderator on at

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@PR001

You should be able to do this is one action that runs in under a second.

Use a Select action on the JSON array.

Switch the Select Map input to a single input box instead of a table.

Use a setProperty( ) expression on the item() https://learn.microsoft.com/en-us/azure/logic-apps/workflow-definition-language-functions-reference#setProperty

Use the name of the key for the property name, then for the value use a replace(item()?[‘InsertKeyName’], ‘ ‘, ‘’)

The Select has an internal looping that will go over each object in the JSON array & set that key property value to the new value without spaces.

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PR001 28 on at

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Thank you Takolota. What if i have to replace the value for all the keys in the JSON array? Specifically, I would like to remove all special characters from the JSON array. Thanks again!

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takolota1 4,974 Moderator on at

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@PR001

For all keys/values, as long as the special characters do not include the JSON array structure characters like “ , : { } [ ] then I would just use a single Compose &…

Use string( ) on the entire JSON array

Outside the string expression add multiple replace( ) expressions, one for each special character to remove.

Outside all the replace( ) expressions use a json( ) expression to return it back from a string to JSON.

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PR001 28 on at

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Great makes sense. Thank you sir!

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