Powerapps Sharepoint.Integration Launch different forms OnNew and OnEdit

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Posted on by Gskinner76

So I have a PowerApps form and I am using the functionality on SharepointIntegration>OnNew to launch the form using the following code

Launch("https://apps.powerapps.com/play/<AppID>",{skipAppMetadata: "true", hidenavbar: "true"},
LaunchTarget.New);
RequestHide();
 
This is working fine but my issue on the Form I have 2 screens, Screen 1 Launches fine as this is onNew and works ok.  Now I have a 2nd
screen on the form that is used for when they want to edit an item from the SP list.  But how do i differentiate in the code to launch
the edit form OnEdit

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Building Power Apps

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Michael E. Gernaey 53,488 Super User 2025 Season 2 on at

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Hi,

Add another parameter like this

{skipAppMetadata: "true", hidenavbar: "true", ScreenToNavigateTo: "NameOfScreen"}

Change the NameOfScreen to the Edit or the New screen depending on what you want the app to do

Turn on the setting Use Navigate in App.OnStart (in the settings)

OR

Use a Home Screen

If you use the App.OnStart do this

Switch(Param(ScreenToNavigateTo), "ScreenNew", Navigate(YourNewScreenName), "ScreenEdit", Navigate(YourEditScreen), Navigate(SetADefaultFormNameHere) );

Or use a Home Screen and use the OnVisible of the Home Screen

Switch(Param(ScreenToNavigateTo),
"ScreenNew",
Navigate(YourNewScreenName),
"ScreenEdit",
Navigate(YourEditScreen),
Navigate(SetADefaultFormNameHere)
);

Either way thats how you do it.

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Gskinner76 37 on at

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Hi https://community.powerplatform.com/profile/?userid=34e98053-5c48-ef11-a317-0022481d08e0

So I tried what you suggested and on SharepointIntegration I have

OnNew =

Launch("https://apps.powerapps.com/play/<AppID",{skipAppMetadata: "true", ScreenToNavigateTo: "NewIncidentTicket", hidenavbar: "true"},

LaunchTarget.New);

RequestHide();

OnEdit =

Launch("https://apps.powerapps.com/play/<AppID>",{skipAppMetadata: "true", hidenavbar: "true", ScreenToNavigateTo: "NewIncidentTicket_EditView", ItemID:SharePointIntegration.SelectedListItemID},

LaunchTarget.New);

Then on App StartScreen I have put the code but i get an error see screen shot below

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