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Launch external URL using field value as parameter

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Posted on by CK-22072023-0

Hi,

I am struggling with launch syntax that would enable me to pass the value of a datafield as a parameter when I click a button. for example, if I wanted to pass the value of MyField to the URL to get the resulting URL opened in the browser where the value of MyField = '123'. The final URL would be: "https://somewebsite.com/account/account.nl?id=123"

Any guidance is appreciated.

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WarrenBelz 153,781 Most Valuable Professional on at

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Hi @ckelsoe ,

Try

"https://somewebsite.com/account/account.nl?id='" & MyField" & "'"

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CK-22072023-0 11 on at

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Hi @WarrenBelz ,

This example helped me a lot. I could not get the exact example to work as expected - I cannot figure out the reference to MyField directly. What I was able to get working is to pull the value from MyField_DataCard via Launch("https://somewebsite.com/account/account.nl?id=" & DataCardValue6). While this works, I really do not want to show the actual data from MyField_Datacard. I want to use the value of that field in the URL. I think that is what your example may represent. However, I am still not able to get it to work as expected.

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WarrenBelz 153,781 Most Valuable Professional on at

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Hi @ckelsoe ,

Firstly the single quotes in my example are used if the parameter is Text (a hyperlink will accept either single or double quotes but double have a different meaning in Power Apps).

Also if you have a numeric value in DataCardValue6

Launch("https://somewebsite.com/account/account.nl?id=" & Value(DataCardValue6.Text))

If MyField is selected in a records from a gallery

Launch("https://somewebsite.com/account/account.nl?id=" & GalleryName.Selected.MyField).

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CK-22072023-0 11 on at

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MyField is the column in the underlying Sharepoint list. Is there not a way to select a column from the list that is not in the gallery?

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WarrenBelz 153,781 Most Valuable Professional on at

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If the Gallery has the ID of the relevant record containing MyField

With( { wField: LookUp( ListName, ID=GalleryName.Selected.ID ).MyField }, Launch("https://somewebsite.com/account/account.nl?id=" & wField) )

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WarrenBelz 153,781 Most Valuable Professional on at

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Hi @ckelsoe ,

Just checking if you got the result you were looking for on this thread. Happy to help further if not.

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CK-22072023-0 11 on at

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I was not successful in pulling the data from the underlying data source. I just added the column to the form then hid it.

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