How to use Launch function in an If

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Posted on by AG-15111838-0

I am generating a pdf with a flow in power automate this returns me a link to download the pdf but I can not get the Launch function to run inside the if, it only works on a button?

If(
    !IsBlank(pdfLink);
    Notify("El PDF ha sido generado ya puedes descargarlo!"; NotificationType.Success);
    Launch("https://cepucmmedu.sharepoint.com/teams/PasantasEICT609" & pdfLink)
);;

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Mark Nanneman 329 on at

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How to use Launch function in an If

Strange... It is possible for me to use the Launch within an If() function. I was able to basically put your formula verbatim into my power app, just changing the syntax for English and it worked.

If you remove the "Notify" action does it work?

I'm glad you found a work around though!
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SaiRT14 1,278 on at

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How to use Launch function in an If

Instead of directly using Launch inside the If, you can manage it with a variable and a separate button or function call.

If(
!IsBlank(pdfLink),
Notify("El PDF ha sido generado, ya puedes descargarlo!", NotificationType.Success);
Set(varPdfLink, "https://cepucmmedu.sharepoint.com/teams/PasantasEICT609" & pdfLink)
)

OnSelect property:

If(!IsBlank(varPdfLink), Launch(varPdfLink))

you can call the Launch function conditionally using a timer component:

Start = !IsBlank(varPdfLink)

Use the OnTimerEnd property to trigger the Launch

If(!IsBlank(varPdfLink), Launch(varPdfLink))
AG-15111838-0 4 on at

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How to use Launch function in an If

You are right Mark Nanneman, it is because of my language that the syntax is a little different, when you use a , I must use ; and when you use ; I use ;;

The if works for me, what I can't achieve is to open immediately the new tab with the link as you say. Surely it is because of what @SpongeYe says, it is not possible and what I am looking for is not to have 2 buttons in the gallery, one to trigger the flow that generates the pdf and another to launch the link and download it.
Mark Nanneman 329 on at

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How to use Launch function in an If

The formula appears to have a syntax issue, unless things are different in your language/region.

For me to get this function to work, I'd have to write it like the following (with a comma after the first If() condition.
Also, I had to add commas for the Notify() function, to set the type and timeout.

And I did test it and it did work--however if you don't set a long enough duration on the notification, you will never see it. It immediately pops you over to the new tab w/ the link.

If you want to force the user to see the notification message, put it in a popup container that is normally hidden, and use your formula to toggle the visibility of the popup component, and have a button there that Launches the link.

If this helped you, please click "Does this answer your question" and give it a like to help others in the community (+ close the ticket)!

Power Platform Developer | LinkedIn: Mark Nanneman | Blog: Power Stuff | YouTube: Mark's Power Stuff | Buy me a coffee
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SpongYe 5,198 on at

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How to use Launch function in an If

Hello,

Launch can only be used in behavior formulas. Launch and Param functions

By selecting a Button control, the user initiates a sequence of actions, or behaviors, that will change the state of the app.

Because these functions change the state of the app, they can't be automatically recalculated. You can use them in the formulas for the OnSelect, OnVisible, OnHidden, and other On... properties, which are called behavior formulas.

Please read through Understand behavior formulas for canvas apps

Hope this helps.