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Best way to make multiple columns in collection the uses Distinct

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Posted on by Jeffclark

135

So I have a collection, and I wanted to make a collection of these items because it is going to be used in a gallery. I thought this was going to make several columns in the collection. However, I realised that using distinct is going to return a table. So, I can no longer use the results in a label inside the gallery. I would appreciate any idea, and help

ClearCollect(
 disPracTeam,
 Distinct(
 'dbJS.ISTaxes',
 isTaxPracTeam
 )

)*/


ClearCollect(
 disPracTeam,
 {
 title: Distinct(
 'dbJS.ISTaxes',
 isTaxPracTeam),
 
 grade: Distinct(
 SortByColumns(
 Filter(
 'dbJS.dealsStaffMngrUps',
 !IsBlank(GlobalGradeName)
 ),
 "crfb2_globalgradename",
 Ascending
 ),
 GlobalGradeName
),
 location: Distinct(
 SortByColumns(
 Filter(
 'dbJS.dealsStaffMngrUps',
 !IsBlank(OfficeLocationCity)
 ),
 "crfb2_officelocationcity",
 Ascending
 ),
 OfficeLocationCity
),
 name: Distinct(
 SortByColumns(
 Filter(
 'dbJS.dealsStaffMngrUps',
 !IsBlank(Name)
 ),
 "crfb2_name",
 Ascending
 ),
 Name
)

 }

);

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WarrenBelz 155,779 Most Valuable Professional on at

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Hi @Jeffclark ,

Firstly, can you please post your code in Text - below is OCR'd so watch spelling - you need to use GroupBy and then "get the columns back"

ClearCollect( disPracTeam, { grade: SortByColumns( AddColumns( GroupBy( Filter( 'dbDS.dealsStaffMngrUps', !IsBlank(GlobalGradeName) ), "GlobalGradeName", "Data" ), "Column1Name", First(Data).Column1Name, "Column2Name", First(Data).Column2Name ), GlobalGradeName ), location: . . . .

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Jeffclark 135 on at

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@WarrenBelz I have updated it to include the full code in text if you still wanted to see it, but I will check out your solution.

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Jeffclark 135 on at

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@WarrenBelz So, I may need a little more explanation on this if you do not mind. I guess I am not understanding the the "data" or column1 and column2 are referring to?
ClearCollect( disPracTeam, { grade: SortByColumns( AddColumns( GroupBy( Filter( 'dbJS.dealsStaffMngrUps', !IsBlank(GlobalGradeName) ), "GlobalGradeName", "Data" ), "Column1Name", First(Data).Column1Name, "Column2Name", First(Data).Column2Name ), GlobalGradeName ) } )

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WarrenBelz 155,779 Most Valuable Professional on at

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Hi @Jeffclark ,

Firstly, you might have a read of the GroupBy guide. You can call Data whatever you want - it is a table field with all the columns and rows (except the grouped column) of the records matching the grouped column. Column1 and Column2 (and 3/4/5 etc) are the columns you need to "get back" as they are sitting in the Data Table - you can however only get back one field value in each (I have used the first one) as you need a single value for the added column.

Please click Accept as solution if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs Up.

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Jeffclark 135 on at

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@WarrenBelz
Something like this?

ClearCollect( disPracTeam, { grade: SortByColumns( AddColumns( GroupBy( Filter( 'dbJS.dealsStaffMngrUps', !IsBlank(GlobalGradeName) ), "crfb2_globalgradename", "globalGrade" ), "global", First(globalGrade).global ), "crfb2_globalgradename", Ascending ) })

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WarrenBelz 155,779 Most Valuable Professional on at

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Hi @Jeffclark ,

Yep - that is about it as long as you have all your list and field references correct.

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