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IfError not work well with Set&Patch combination

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Posted on by Sank

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Hi,

IfError doesn't work when using code like this:

IfError(Set(varID,Patch(...),Notify("Error"))

Any ideas?

Nelson

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CarlosFigueira on at

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The Set function will not return an error. In a formula such as Set(var, expression), if expression is an error then the value of 'var' will be that error - Set did what it was supposed to do. For your scenario, you can have something like the following:

Set(varId, Patch(...)); IfError(varId, Notify($"Error: {FirstError.Message}"))

Hope this helps!

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Wood_Raymond 20 on at

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@CarlosFigueira in this case if the Patch throws an error will it be an unhandled error and be caught by App.OnError??

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CarlosFigueira on at

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No - when we save the result of the Patch in a variable using the Set function, we are handling the error ourselves (by storing it). So it will not bubble up to the App.OnError handler.

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Wood_Raymond 20 on at

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Thanks @CarlosFigueira . Makes perfect sense when you put it like that. Cheers.

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