Remove decimals from Artikel #

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Posted on by Rapaille

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Hello all,

I'm a new Power Apps user and I'm trying to build an app.

I have a list 'A' which pulls the 'Artikel #' from list 'B' by using the lookup function. In list 'B' the format of the 'Artikel #' column is value with no decimals and the number is shown as 3014470.

When I want to display the 'Artikel #' on the detail screen, the value shows with 7 zeros after a period (3014470.0000000). I tried to figure it out for a long time, but no success.

Who can help me with this issue?

Thank you in advance for you kind cooperation.

Kind regards,

Hans

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Building Power Apps

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iAm_ManCat 18,256 Most Valuable Professional on at

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You could use either:

Round(ThisItem.'Artikel #',0)

or

Text(ThisItem.'Artikel #', "#")

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lucarios1705 16 on at

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for me was working the function: Round(Substitute(Gallery1.Selected.xxxx;".";",");0)

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Rapaille 162 on at

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Thank you both for your help. I tried all three options, but still same issue.

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iAm_ManCat 18,256 Most Valuable Professional on at

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Ah ok, inside a datacard like that probably going to be able to use parent.default:

Round(Parent.Default,0)

or

Text(Parent.Default, "#")

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Rapaille 162 on at

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Unfortunately still same issue.

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iAm_ManCat 18,256 Most Valuable Professional on at

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Hi, you've put that in the displaymode property (which should be its original value of DisplayMode.View), the formula needs to go into the Text property to replace the Text its currently showing

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Rapaille 162 on at

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For this field text is not present in the dropdown. Could you please help me with the correct option?

Thank you in advance.

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iAm_ManCat 18,256 Most Valuable Professional on at

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What type of control is it? Could you please post a screenshot of the tree view on the left with that control selected?

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Rapaille 162 on at

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iAm_ManCat 18,256 Most Valuable Professional on at

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hmmm,

We could do something like this for your items property, but you will need to replace my column names and datasource names with your own:

ForAll(Choices([@YOURDATASOURCE].YOURCOLUMNNAME), First(Split(Value, ".")).Result)

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