So i love how with standard field types, if i want to get a value I can do this, and it gets picked up by vs code:
this._value = context.parameters.INPUTFIELDNAME.raw;
With datasets though I need to do this:
valuePara.textContent = gridParam.records[currentRecordId].getFormattedValue("INPUTFIELDNAMESTR");
It would be nice if the API allowed me to do this:
context.dataset[i].INPUTFIELDNAME.raw
I know it's a minor thing, but if you look at that dataset example.. there's alot of code just to sort columns, then grab a record, then build a grid:
I'm thinking we can probably replace several functions and achieve the same with a single method that looks like this:
/** pseudocode **/
context.dataset.sort(sortonthiscolumn);
for(int i=0; i<dataset.length; i++){ console.log (context.dataset[i].columnname.value); }
Does that make sense or am I just being lazy? 😄
Given no more responses.. I will accept your solution sir
Hi Andrew,
My understanding is that getSortedColumnsOnView() is just an optional method. It just removes system columns and sorts the columns. You can choose to skip it.
It seems that dataset is a dictionary object, rather than an Array object. However, it is also logical to query data records by GUID rather than by index (1,2,3...N)
The SDK does give you a list of the all the GUIDs through the DataSet.sortedRecordIds() method which you can use to traverse the whole Dictionary like below
for(let currentRecordId of DataSet.sortedRecordIds){
let name = DataSet.records[currentRecordId].getFormattedValue(columnItem.name);
}
I agree with you that DataSet's API can be refined bit more to make is easily consumable but there may be internal complexities in refactoring its collections. Hopefully better by GA.
WarrenBelz
85
Most Valuable Professional
Michael E. Gernaey
65
Super User 2025 Season 1
mmbr1606
55
Super User 2025 Season 1