Unanswered

User Defined Functions : Play issue

(0) Share

Report

Posted on by AntoineB1

Hello,

I have written a function in App.Formulas that works correctly in the edit mode of the app.
However, I noticed that since I enabled "User-Defined Functions" in the settings, the application publishing does not update correctly in play mode.
When I launch the application in play mode, it indicates that there is an update:

"A new version of this app is coming. We'll let you know when it's available."

But it never actually updates.

The issue is resolved when I disable this feature.

Do you know any solutions to resolve these issues?

Thank you!

Categories:

Experimental features

I have the same question (0)

All responses (19)

Answers (0)

Sort by

PeterCBell_au 109 on at

Like
a
(0)

Report
Copy link

Link copied!

I have the same issue.

Was this reply helpful? Yes No
PeterCBell_au 109 on at

Like
a
(0)

Report
Copy link

Link copied!

Correction; didnt disable feature but didnt define any UDF --> corrected problem.

Was this reply helpful? Yes No
AntoineB1 2 on at

Like
a
(0)

Report
Copy link

Link copied!

Hello, thank you for your response.
My issue is specifically that I am trying to use this functionality, but I cannot publish my application in play mode after enabling it.
Therefore, there is no point in activating this feature unless it can be used in play mode.

Was this reply helpful? Yes No
ShantanuP Microsoft Employee on at

Like
a
(0)

Report
Copy link

Link copied!

Can you please share session-id for this issue?

Was this reply helpful? Yes No
PeterCBell_au 109 on at

Like
a
(0)

Report
Copy link

Link copied!

try mine since same issue. Peter.
Session ID: 204d1be3-bb03-43a3-a975-ef4fb3b7d5c6
PowerApps 3.24014.14
Object ID: 9eca0026-55e4-470f-a497-27744dde6ac6
Tenant ID: a687a7bf-02db-43df-bcbb-e7a8bda611a2
Embedded Correlation ID: 2da96d60-c24e-11ee-801f-c925fdb2a61d
App ID: 7ef7bcc6-bb64-4dde-ac28-236bfb6315d9
Telemetry location: global

Was this reply helpful? Yes No
ShantanuP Microsoft Employee on at

Like
a
(0)

Report
Copy link

Link copied!

Hi @PeterCBell_au , Can you please share your player session id where App fails to load? Above seems to be authoring session id. Thanks!

Was this reply helpful? Yes No
PeterCBell_au 109 on at

Like
a
(0)

Report
Copy link

Link copied!

I enabled a single UDF without referencing it and the problem persists
Session id 94463370-343f-4dfc-9cc7-2d3f9bb668f0
authoring version 3.24015.12

I will leave it as the published version for the moment.

Was this reply helpful? Yes No
PeterCBell_au 109 on at

Like
a
(0)

Report
Copy link

Link copied!

published weblink if that is what you are after?
https://apps.powerapps.com/play/e/default-a687a7bf-02db-43df-bcbb-e7a8bda611a2/a/7ef7bcc6-bb64-4dde-ac28-236bfb6315d9?tenantId=a687a7bf-02db-43df-bcbb-e7a8bda611a2&hint=d61ddb65-9702-4d32-90a7-2f755a2e9b73&sourcetime=1707296860932

Was this reply helpful? Yes No
ShantanuP Microsoft Employee on at

Like
a
(0)

Report
Copy link

Link copied!

Hi @PeterCBell_au ,

Can you please share how you have declared UDF? I will try to repro the issue on my end that way.

Was this reply helpful? Yes No
PeterCBell_au 109 on at

Like
a
(0)

Report
Copy link

Link copied!

udfMeetingBaseColour(UnitName: Text,isImportant:Boolean) :Color=If(isImportant,Color.Yellow, If( IsBlank(First(Filter(UnitColours,ColUnit=UnitName))),Color.NavajoWhite, First(Filter(UnitColours,ColUnit=UnitName)).fCol ))

The UDF is using a collection 'UnitColours' to perform the calculation. Is this the problem?

The collection has some logic to create the collection from a text string stored in a sharepoint table. I doubt that matters, just create a collection with the same record structure to test it at your end.
ClearCollect(UnitColours,{ColUnit:"",fCol:Color.Black});Clear(UnitColours);
//Extract the key:colour values
ForAll( ForAll(Split(gblMeetingColours,VertBar), {Result: ThisRecord.Value}),
If(!IsBlank(TrimEnds(Result)),
Collect(UnitColours,
{ColUnit:TrimEnds(First(ForAll(Split(Result,","), {Result: ThisRecord.Value})).Result) , fCol:ColorValue(TrimEnds(Last(ForAll(Split(Result,","), {Result: ThisRecord.Value})).Result))}
)
)
);

Was this reply helpful? Yes No