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Saving Forms From A Component

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Posted on by bn_powerapps

I am trying to create a few centralised components so I do not have to keep writing the same code. So far got most of it working but I am trying to figure out how to SubmitForm from inside a component.

Normal code for this would be something like this - SubmitForm(form_name)

Tried passing the name of the form to the component via txt input. But Component does not like the fact it's not an editable form.

I can not see an component input for forms to pass it for submit.

The save part of the component needs to go every page so would save me a lot duplicate code.

Tried using behaviour component as well.

Any thoughts has anyone else done this?

Thanks

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Building Power Apps

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rb 835 Super User 2024 Season 1 on at

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Hi, assuming you mean the Form is outside your component, I recently authored a post which might be of help. It's the only way I've found to reliably trigger action in the Parent app from inside a component-scope: https://powerusers.microsoft.com/t5/Building-Power-Apps/navigate-in-component-context-variable/m-p/1664587/highlight/true#M423811

In your case you may have:
Component:
Button OnSelect:
Set(ToggleSubmitForm, false);
Set(ToggleSubmitForm, true);
Output Property 'SubmitFormTrigger' with value (which will be toggled by button above):
ToggleSubmitForm
App Screen
Add Component with name 'compSubmit_ScreenName'
Add Toggle with name 'toggle_SubmitForm_ScreenName'
Visible:
false
Default:
compSubmit_ScreenName.SubmitFormTrigger
OnCheck:
SubmitForm(Form1)
Then you can just copy the Component + Toggle to each screen you need it, and update the Form reference of your Toggle OnCheck.

Let me know if this works?

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bn_powerapps 8 on at

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Thanks will take a look and see how it goes.

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bn_powerapps 8 on at

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Worked had to make a few changes but the overall idea was right. Shame it can not be done soley within a component via inputs / outputs / behaviours. Kind of defeats the object.

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