Format date from a datepicker in Julian date format

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Posted on by twistsd

Hi,

I am new to using Power apps.

I am trying to copy the date from a date picker in one datacard to another datacard and dsiplay it in Julian Date format( 21/2/22 to be displayed as 22052). I have managed to copy the date and tried using the format of "yyddd" but that displays the date as "22Mon".

Any help would be gratefully appreciated.

Thanks

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Dant7484 154 on at

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Hi,
I tried this and it worked but is kinda ugly lol
Set( _month, Text( DateTimeValue(DatePicker3.SelectedDate), "[$-en-GB]mm" ) ); Set( _day, Text( DateTimeValue(DatePicker3.SelectedDate), "[$-en-GB]dd" ) ); Set( _jDay, Switch( _month, "01", "0" & _day, "02", "0" & Value(_day)+31, "03", "0" & Value(_day)+59, "04", "0" & Value(_day)+90, "05", Value(_day)+120, "06", Value(_day)+151, "07", Value(_day)+181, "08", Value(_day)+212, "09", Value(_day)+243, "10", Value(_day)+273, "11", Value(_day)+304, "12", Value(_day)+334 ) ); Set(julianDate, Text( DateTimeValue(DatePicker3.SelectedDate), "[$-en-GB]yy" ) & _jDay)
If you want to use it as a number u need to convert it with Value(julianDate) otherwise you can just use it as it is to show the Julian date of the date picked. Good luck!

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twistsd 65 on at

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@Dant7484

Thanks for the reply.

Where would I put that code?

Thanks

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Dant7484 154 on at

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No problem, though a good thing you replied because I just saw I forgot the leap year case (add 1 day after February).
Put this code in the date picker OnChange :

Set( _month, Text( DateTimeValue(DatePicker3_1.SelectedDate), "[$-en-GB]mm" ) ); Set( _day, Text( DateTimeValue(DatePicker3_1.SelectedDate), "[$-en-GB]dd" ) ); Set(_leapYear, If(Month(Date(Year(Now()),2,29))=2, 1, 0)); // If leap year add 1 to _jday Set( _jDay, Switch( _month, "01", "0" & _day, "02", "0" & Value(_day)+31, "03", "0" & Value(_day)+59 +_leapYear, "04", "0" & Value(_day)+90 +_leapYear, "05", Value(_day)+120 +_leapYear, "06", Value(_day)+151 +_leapYear, "07", Value(_day)+181 +_leapYear, "08", Value(_day)+212 +_leapYear, "09", Value(_day)+243 +_leapYear, "10", Value(_day)+273 +_leapYear, "11", Value(_day)+304 +_leapYear, "12", Value(_day)+334 +_leapYear ) ); Set(julianDate, Text( DateTimeValue(DatePicker3_1.SelectedDate), "[$-en-GB]yy" ) & _jDay)

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Dant7484 154 on at

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Edited leap year formula

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twistsd 65 on at

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@Dant7484

Thanks for the update.

I have just tried it but it still displays the date as 22/02/2022.

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Dant7484 154 on at

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Hi, are you trying to display it in another date picker? because it wouldn't work, put julianDate in a textinput to display the value if you want to test it

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twistsd 65 on at

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@Dant7484

Thanks.
That is what I am trying to achieve. I have a datepicker to choose the date and then I want a textinput to display the value in julian date format. Could you please give me the steps I need to complete to achieve this.

Thanks

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Dant7484 154 on at

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Of course no problem. You might have to unlock the input in datacard to edit Default

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Dant7484 154 on at

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The number on the input is wrong somehow but when I picked the date its fixed idk how

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twistsd 65 on at

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@Dant7484

Thanks

I have tried that but the data card for the juilan formatted input stays blank

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