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Http Request GET query param

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Posted on by Anilal Gopinathan

Hi Experts,

In my Topic-HTTP Request,
I need to pass the value which i captured and set in the variable StrAddress to the below API as query param

I tried the below
https://www2.moxxxxxxxxx.org/snowapi/mymxxxxxxxy.svc/SnowStreet2017?a={StrAddress}
https://www2.mxxxxxxxxxxx.org/snowapi/mxxxxxxy.svc/SnowStreet2017?a={Topic.StrAddress}

Any thoughts or help, please see the screen shot for clarity

Getting error -

Error Message: HTTP request failed with status code 400 BadRequest. Error Code: HttpRequestFailure Conversation Id: fd7b0201-xxx-a9e2-3d9xx3ac23 Time (UTC): 2024-07-17T15:23:37.944Z

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Mahesh Chintha 158 on at

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Use Variable management -> Set a variable value and use 'Formula' to build the URL and then use it as a variable in the HTTP Request

"https://www2.moxxxxxxxxx.org/snowapi/mymxxxxxxxy.svc/SnowStreet2017?a=" & Topic.StrAddress

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Anilal Gopinathan 2 on at

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@mahesh,

The approach started working, but getting error with url encoding, tried the below two options, still throwing error,

generated url is -> https://www2.mxxxxxxx.org/snowapi/myxxxxx.svc/SnowStreet2017?a=9604 Oak Ln—> -- See the space in the url for the a-value

Tried these below options, still throwing error,

"https://www2.mxxxxxxx.org/snowapi/myxxxxx.svc/Snxxxxxxx2017?a=" & {encodeUriComponent(Topic.StrAddress)}

"https://www2.mxxxxxxx.org/snowapi/myxxxxx.svc/Snoxxxxxxx2017?a=" & {=encodeUriComponent(Topic.StrAddress)}

Error - Error Message: HTTP request failed with status code 400 BadRequest

Update - fx = "https://www2.moxxxxxx.org/snowapi/myxxxxxxxx.svc/Snxxxxxxx2017?a=" & EncodeUrl(Topic.StrAddress) -- this worked

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