validating if numbers and letters are in a text input

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Posted on by Erandi

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Hi,

I want to validate "123801902V" or "201923920v" text filed in a form in the power app .How I do it?

there should be 9 digits and one letter .

Thank you.

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Building Power Apps

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mmbr1606 14,629 Super User 2026 Season 1 on at

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hey @Erandi

is it always the letter V or any letter? what is ypir exact use case? so what happens when the validation is true?

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ANB 7,252 Super User 2026 Season 1 on at

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HI @Erandi , You can use IsMatch. Check this:
https://www.matthewdevaney.com/data-validation-for-power-apps-forms/

https://learn.microsoft.com/en-us/power-platform/power-fx/reference/function-ismatch

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ANB

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enriqueglopez 516 Moderator on at

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You can use IsMatch function to compare your input value with a RegEx.

For example:

IsMatch(TextInput.Text, "^\d{9}[a-zA-Z]$")

This Regex will help to reach what you want. You could do the validation like this:

If( IsMatch( TextInput.Text, "^\d{9}[a-zA-Z]$" ), "Input is valid", "Input is not valid" )

Ref: IsMatch, Match, and MatchAll functions - Power Platform | Microsoft Learn

If this post helps, then please consider Accept it as the solution to help the other members find it.

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Erandi 265 on at

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Hi @mmbr1606 ,yes it can be "V" and "v". That is a ID number pattern. So i want validate it when submitting to form.

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ANB 7,252 Super User 2026 Season 1 on at

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@Erandi Try this
IsMatch( TextInput1.Text, Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Letter )
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ANB

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Erandi 265 on at

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Hi guys,
If I use the numbers between 0 to 9, it should be
IsMatch(txtNIC.Text, "^\d[0,9][z-Z]$") ,

am i right?

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Erandi 265 on at

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hi @enriqueglopez ,
i tried but i am getting error like this.

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enriqueglopez 516 Moderator on at

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Use this one instead

"^\d{9}[vV]$"

This Regex will validate that the first 9 characters are a number and the last is V or v.

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ANB 7,252 Super User 2026 Season 1 on at

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@Erandi If last letter will always "V" or "v", this should also help you
IsMatch( TextInput1.Text, Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Digit & Match.Letter ) && ("V" in TextInput1.Text || "v" in TextInput1.Text)

You can add above thing in the condition.

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I hope this helps.

Please click Accept as solution ✅ if my post helped you solve your issue. This will help others find it more readily. It also closes the item. If the content was useful in other ways, please consider giving it Thumbs up.👍

Thanks,
ANB

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Erandi 265 on at

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Hi guys,
then if i want to validate 6 digits long ID.can I use like this?
If(
Len(txtEmplID.Text) = 6,

UpdateContext({varShowErrorMsg:"Employee ID contains 6 digits"});
UpdateContext({varShowError:true});
Reset(txtEmplID);
)

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