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How to pass Datacardvalue along with URL in Launch() in Powerapps

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Posted on 3 Sep 2020 05:54:19 by Community Power Pla...

In Powerapps, I am having a Button(View Report). In Button Onselect : Launch("http://Server/reports/report/folder/reportname"). With this formula I am getting all the records in the report.

But, I should display records based on TEST_ID. Now along with that URL, I need to pass Test_ID Datacardvalue. Based on that Test_ID, the SSRS report must be filter in browser. In below, SSRS Report, the table must be filter according to the Test_ID passing from Powerapps.

For this, In Button Onselect : Launch("http://Server/reports/report/folder/MFTestTaskMap" && Test_IDDataCardValue). This formula is not working.

Can anyne help me how to solve this.

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Using Apps Using Formulas

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v-siky-msft on 08 Sep 2020 at 03:00:54

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Re: How to pass Datacardvalue along with URL in Launch() in Powerapps

Hi @Anonymous

Refer to this article, to set a report parameter within a URL, use the following syntax:

parameter=value

Hence, define 'Test_ID' as a parameter in the report, then use the following URL:

Launch("http://Server/reports/report/folder/reportname&Test_ID="&Test_IDDataCardValue.Text)

Hope this helps.

Sik
timl 35,202 Super User 2025 Season 2 on 03 Sep 2020 at 08:49:34

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Re: How to pass Datacardvalue along with URL in Launch() in Powerapps

Hi @Anonymous

I would try this...

Launch("http://Server/reports/report/folder/MFTestTaskMap" & Test_IDDataCardValue.Text)