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Dear Power users,
I've created an App using a database from a Sharepoint list, and this App contains multiple pages.
Each page corresponds to a specific section of the list (General informations, Quality, Security, ... etc).
I duplicated my "FormNewCase" from the first page to each page (the name changes by FormNewCase_1, FormNewCase_2, ... etc) and I selected questions from the right section.
On each page, I've inserted a "next" button with the following command :
[action, on select:] Navigate(Quality, ScreenTransition.Fade) => to go to the Quality section
On the last one I've inserted a "record" button to validate data in my Sharepoint list with the following command :
[action, on select :] SubmitForm(FormNewCase)
When I click on the record button data are not saved on my sharepoint list ! 😕
What do I forget ?
Thank you in advance for your support...
OK guys, I solved my issues.
Everything works well now.
Thank you for your support.
Hi all,
In order to start on a good base, I created a new Sharepoint list.
What I've done is to test step by step and see what works and doesn't work.
1- If I submit only the first page (FormNewCase), with the following script : on select=SubmitForm(FormNewCase) on the button "next" => data in my sharepoint list are recorded.
2- If I submit The two first pages (FormNewCase and FormNewCase_1), with the following script : on select=SubmitForm(FormNewCase); SubmitForm(FormNewCase_1) on the button "next" => data from the FormNewCase are recorded in the sharepoint list but not data from FormNewCase_1.
Hello Kris and sorry to answer lately.
So about the "next button" that's what I have done.
About the "record button", when I click on it the app stays on the last page and my record doesn't work. 😕
Hi @Anonymous,
Could you please show a bit more about your SharePoint list?
When you save data from your PowerApps app to your SharePoint list using Submit() function, you must make sure all required fields of your SP list are filled with value. In addition, the Submit() function only take effect on only one EditForm once time.
If you use Submit(FormNewCase) formula within OnSelect property of Button control in the last page (Screen), this function could only submit form data within your first screen.
I assume that you have three Screens (Pages) within your PowerApps app, I have made a test on my side and please take a try with the following workaround:
Navigate(Screen2,ScreenTransition.Fade)
Navigate(Screen3,ScreenTransition.Fade)
Patch(StudentInfo,Defaults(StudentInfo),FormNewCase.Updates,FormNewCase_2.Updates,FormNewCase_3.Updates)
Note: The StudentInfo is a SharePoint list datasource within my PowerApps app. On your side, you should type the following formula within OnSelect property of the Record Button control:
Patch(YourSharePointListDatasource,Defaults(YourSharePointListDatasource),FormNewCase.Updates,FormNewCase_2.Updates,FormNewCase_3.Updates,...,FormNewCase_n.Updates)
Best regards,
Kris
May be this helps you as well:
so you are sure you did bind all the forms to the same datasource and same record (may be gallery.selected)
Update property of each datacard is set to the right control
and onFailure of form2 and 3 is not triggered ?
Did you try to save only one form? let's say form2 with an additional temporary button trigger the Submit for form2.
If it is not updating sharepoint list than you need to check all the mentioned properties.
I'm back... So I made the modification and I don't have error but on my sharepoint list I have only the first part record (FormNewCase and not the others)
Many thanks for your quick answer... I'm going to check and come back ASAP...
Ok I get it now.
You basically have not one but 3 forms.
When you press the button you submit actually only one form which is by the name the first one.
You should submit all of them by writhing another 2 commands after the first submit:
OnSelect = SubmitForm(FormNewCase); Submit(FormNewCase_2);Submit(FormNewCase_3)
You will find below some screenshot of what I did.
Database informations
information of the database
validation button
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