Solved: multipart/form-data

multipart/form-data

I have a webhook from an external app. That is sending files that are submitted.

I have a flow

I have a trigger in the flow "When an HTTP Request is received"

The webhoook sends as "multipart/form-data" type

So cant generate a schema, just leave blank.

Can't parse json, since not json

I can try to do splits, replaces, etc.

But it is very messy and it seems like when you convert to string for the replaces, it changes the base64 content to something else? XML?

What is the best way to do this? Below is an example of what the webhook sends.. the content has been removed from the word document, there will always be 1 resume, 1 aadhar card, 1 pan card but could be multiple pay documents...:

{
"$content-type": "multipart/form-data; boundary=1924ec1e13c",
"$content": "<CONTENT BASE64>",
"$multipart": [
{
"headers": {
"Content-Disposition": "form-data; name=\"pancard\"; filename=\"resume.docx\"",
"Content-Type": "application/x-tika-ooxml",
"Content-Length": "14777"
},
"body": {
"$content-type": "application/x-tika-ooxml",
"$content": "<CONTENT BASE64>"
}
},
{
"headers": {
"Content-Disposition": "form-data; name=\"aadhardcard\"; filename=\"aadhar.txt\"",
"Content-Type": "text/plain",
"Content-Length": "6"
},
"body": "aadhar"
},
{
"headers": {
"Content-Disposition": "form-data; name=\"payslips\"; filename=\"pay2.txt\"",
"Content-Type": "text/plain",
"Content-Length": "3"
},
"body": "pay"
},
{
"headers": {
"Content-Disposition": "form-data; name=\"payslips\"; filename=\"pay.txt\"",
"Content-Type": "text/plain",
"Content-Length": "3"
},
"body": "pay"
}
]
}

Categories:

Business Process Flows

Apply the steps below to get each file from multi-part format.

First you need to get muiltpart content. for that you need to use the compose using the following expression

triggerBody()?['$multpart']

it will give to you the array of the files, so you will now using apply for each with the result of the compose

Now you will be able to loop over the files send. So now we will get the binary and the file name

Get the file

Inside the "Apply to each" use the compose action with the following expression:

item()?['body']

Get File Name

Inside the "Apply to each" use the compose action with the following expression:

replace(split(split(item()?['headers/Content-Disposition'], 'filename="')[1], '"')[0], '\"', '')
 
and now you can try to receive a new file.
 
in your flow you will see that you got the file binary and file name
 
Hope that helps you!
 
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