Make visible which record is selected in a gallery

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Posted on by AGroegelich

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Hi All,

I have an app in tablet format (landscape). On the left side there is a gallery and on the right side there is a detail form which shows detailed information of one of the records on the left side.

I am looking for a way to make visible which record is selected in the gallery on the left side. For example I could make the text of selected record bold. (And of course set it to normal when another record is selected). How can I do that?

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Community Power Pla... Microsoft Employee on at

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@AGroegelich
You can utilise the Fill, Color, TemplateFill, other properties of your gallery to do what you want. Most apps I've seen use the TemplateFill property. How to use any of these could be like this:

Gallery1.TemplateFill = If(ThisItem.IsSelected, LightBlue)

Use the If() statement on labels inside your gallery by adding it to the Fill or Color properties.

On loading the screen for the first time the first gallery item will be LightBlue but that's because PowerApps will, by default, always select the first item in this instance.

You can choose whatever color you like, I've just used LightBlue as an example.
emauerbach 124 on at

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Haven't dealt with a gallery in that way, but I would guess that you'd need to set a context variable on select and modify the Fill property based on that condition. The OnSelect for the item:
UpdateContext({SelectedItem: GalleryDisplay.Selected}); Navigate(ItemDisplay,ScreenTransition.None);

Then the Fill property would look like:
If(SelectedItem in {ItemId}, RGBA(255,0,0,20%), RGBA(0,0,0,0))
WarrenBelz 156,576 Most Valuable Professional on at

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Hi @AGroegelich ,
Please accept @Anonymous 's post - this is exactly what I do on all my galleries.
AGroegelich 140 on at

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Hi Eelman,

I wasn't aware of the TemplateFill property so I decided to do that. Works perfect for what I needed. Thanks.
AGroegelich 140 on at

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Hi eauerbach,

Thank you for your suggestion. Unfortutate I couldn't get it working. The {ItemId} is giving an error. Still something I have to learn what that is. I just started with PowerApps last week. I will keep it in mind as another solution.