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Power Platform Community / Forums / Power Apps / Getting multiple choic...
Power Apps
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Getting multiple choices as a dropdown in PowerApps from SharePoint List

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Posted on by Microsoft Employee

Hello Forum, 

 I have a scenario where i have to use multiple choices from SharePoint list  as a dropdown function in a PowerApps and i have tried multiple formula like Distinct, Concat and choice but no result, Anyone in the community has an idea to address the issue 

Thank you in advance. 

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  • Community Power Platform Member Profile Picture
    Microsoft Employee on at

    Hi @Anonymous ,

     

    Use formula in default of dropdown - choices([@datasource].columnname).

    Thanks,

    Chitrakant27

  • Community Power Platform Member Profile Picture
    Microsoft Employee on at

    Hi @Anonymous ,

     

    sorry bro use  same formula in item property in drop down

     

    Thanks,

    Chitrakant27

  • Community Power Platform Member Profile Picture
    Microsoft Employee on at

    Hi @Chitrakant27 , 

    Thank you for the suggest, I have tried that formula but doesn't work as the fields in the SharePoint is choices and they have multiple choices already updated, now they have to be used as a filter in the PowerApps, 

    So it is not a single choice but of a multiple choice 

    Hope this helps 

     

  • Community Power Platform Member Profile Picture
    Microsoft Employee on at

    Hi @Anonymous ,

     

    Can you use combo box as like , I used in below and apply property in items.

     

    Chitrakant27_1-1668448740529.png

     

    Chitrakant27_2-1668448774487.png

    Thanks,

    Chitrakant27

  • Verified answer
    v-qiaqi@microsoft.com Profile Picture
    Microsoft Employee on at

    Hi @Anonymous,

    Have you solved your problem?

    Do you want to get the whole Choice column values as the dropdown list options?

    Could you please tell me that if this Choice column allows multi select?

     

    If you want to get distinct choices from the Choice column in SP list, you just need to set the Items property of the Combo Box as below:

    ForAll(Distinct(List,ChoiceColumn),Result)

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