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Power Platform Community / Forums / Power Apps / GalleryView that is li...
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GalleryView that is link to SharePoint - Creating Apps

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Posted on by

I have an app that is linked to SharePoint via Power Apps. Whenever I add info in app, it will automatically update the SharePoint too.

As you can see on the attached file, I cannot edit the details for button Spend JPY as it is in GalleryView and will allow me to edit the Spend button only since it is the main BrowseGallery.

 

Is there a way to edit the Spend JPY button using the Browse Gallery to enable the OnSelect script to launch to their respective sites?

 

the OnSelect for Spend button is: Launch("https://pd.e1.jll.com/jde/E1Menu.maf",
{name: "webpage tile"},
LaunchTarget.New)

gumban_daria02_0-1718319310568.png

Spend button.png
Categories:
  • Gerard Simpson Profile Picture
    2,987 Moderator on at

    Hi @gumban_daria02 - create this table in the Gallery 'Items' property, which contains the details you need. Update the ??? in the second table row:

     

    Table(

    {

    spendType: "Spend",

    url:"https://pd.e1.jll.com/jde/E1Menu.maf",

    name: "webpage tile"

    },

    {

    spendType: "Spend JPY",

    url:"https:????????",

    name: "??????"

    }

    )

     

    Then for the gallery button 'Text' make it: ThisItem.spendType

    For button 'OnSelect' make it: Launch(ThisItem.url, {name: ThisItem.name}, LaunchTarget.New)

     

    Hope this helps

  • SennyT2101 Profile Picture
    4 on at

    If you are not adding any collection of buttons, you can have another way, like the way that AmDev mentioned, but instead of Table(), is just a pair of []

    For example: 

    [

    {

    spendType: "Spend",

    url:"https://pd.e1.jll.com/jde/E1Menu.maf",

    name: "webpage tile"

    },

    {

    spendType: "Spend JPY",

    url:"https:????????",

    name: "??????"

    }

    ]

     

    And if you wish to add more button, you can add more object like this into the [] or Table(), separated by comas:

    {

    spendType: "????",

    url:"https:????????",

    name: "??????"

    }

     

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